An arc which subtends and angle of 60° at O is shown below. Find the ratio of r : R.
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiXH-i8dT-TQOtGU1GWSkplgN-taYKEGmo4qQ_fu5wwSGtveVmENRx6K2c6y1hguikeqYAJFK71IK62VgkXNcOg_hXj5pdUmFh6tkPip6aBg6xhMn9cnXTEKDTjpBLOqaEs8jr8zg95yCoA/s400/Circle+and+trigonometry.jpg)
Select the correct answer from the following choices.
i) 1 : 2
ii) 1 : √2
iii) 1 : √3
iv) 1 : 3
Solutions:
With reference to the following diagram;
![](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgi21NYrgEVFzenZOWUDygBhVU6-rT-VBktqm9xv4dTyBPBqNNIg5whBel9QTZqrTm_PQsi_bicitI28h3tp4pzWuNNakP6_d9Mqm8rnVL1KshfWRM2kfvh36sKbSXfBpa5NBwwvhsGUzWq/s400/Circle+and+trigonometry+-+1.jpg)
The radius ABO passed through the center of the circle ARC and bisects the angle EOD.
Triangle BCO is a right angled triangle with angles 30°, 60° and 90°.
By trigonometry,
if BC = r, then BO = 2r.
Therefore radius of the arc DAE = AB + BO = 3r
Given that the radius of the arc DAE = R,
That is, R = 3r
Therefore the ratio of r : R is 1 : 3.
The answer is (iv).
Reference
- Hey Math! assignment (E-Maths), July 2010, Question #7, Circle and trigonometry
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